Continuing with my musing.
Apparently, AFRL had 2000 lb warhead with 3000 lb motor in mind:
The United States Air Force is addressing the challenges of a new generation of “hard target” engagements through a recent broad agency announcement releas
www.defensemedianetwork.com
But this obviously would have become AGM183 size and wouldn't fit into a IWB.
Assuming "old" rocket motor was originally used for sizing, I'm applying the new heavy loaded grain that gives 1.5x improvement.
Hence, instead of the old 3000 lb motor the new motor only needs to be 2000 lb. The new mass ratio become 1:1.
I assume the F22 will only be used for escort and support behind the F47 I remove it from consideration as a carrier platform.
This leaves the F35's bay as the minimum size. Considering a conventional cylindric form I get about 2050 lb as the pure missile size limit. I think a hybrid rectangular form would be best but that's a bit too troublesome for a quick and dirty attempt.
That gives me ~1285 lb for warhead and motor respectively. Using the GBU72 as a base for scaling I get 0.662361x, hence, a diameter of 11.92" and a length of 74.62" for the penetrator.
That leaves 81" for the motor with a 18" diameter which gives me ~1045 lb.
The remaining 240 lb will go over the warhead for at least 33.2" without tapering.
It's almost only about 20% of the GBU72's destructive content which might not be sufficient for destroying much of a bunker.
Edit: Based on rule of thumb and based on the speed requirement given I assume minimum penetration depth to be ~130 ft=40m.
For 200 ft hypersonic velocity is necessary..