Ballistic missiles have a static trajectory. Therefore, there is no need to scan at a wide angle (elevation angle). This also supports the smaller antenna height. By eye, the aspect ratio of TPU-2 is about 1: 3. With an effective area of 6 m2, we get sides of about 1.4 * 4.3. The solid angle is about 1 square degree at a wavelength of 0.03. . Scanning with such a beam will take 27 seconds. Which is quite acceptable for such radars.
Firstly, whether ballistic missile have static trajectory or not is irrelevant, you are searching to find them inside a volume of space, ballistic missiles can climb to much higher altitude so the elevation is higher. We are basically comparing between 2000 km in height vs about 18 km in height, you need much higher elevation to track ballistic missiles.
Secondly, the area of TPY-2 isn't 6 m2 but 9.2 m2.
and its side isn't 1.4 meter unless you think these guys in this photo are all dwarf
SBX radar is even bigger than TPY-2
Based on my experience, I know that the scanning sector of such radars in standby mode is 90 * 15
No one with experience would confuse between atmospheric attenuation and basic free space basic path loss
I'm tired. I showed you that two radars with the same scanning and energy properties, but different in wavelength (1.1 m and 0.03 m) will have different losses. This difference is 31 dB. Do you agree with that?
You wouldn't be tired if you just took my advice, open a book and learn the different between atmospheric attenuation and basic free space basic path loss

Secondly, as I explained earlier, the free space path loss is caused by the spread out of radio wave as they propagate through space, it is literally the inverse square law working.
Before you argue "why does the loss increase with frequency if they both follow the inverse square law", remember that you compared the two radar with same beam width, but one radar use VHF frequency and the other one use X-band. That lead to the aperture area of your VHF radar being 111.5 m2 and the aperture area of the X-band radar being 0.082 m2, in other words, the VHF radar in your example is
1359 times bigger than the X band radar. Because this free space path loss is literally the spread of beam over distance, a bigger radar aperture will collect signal from greater area, and that why the loss is less for bigger antenna even though both follow the inverse square law principles. I repeat again, this has nothing to do with atmospheric attenuation
However, when you put everything inside Rmax equation, and there isn't an insane size different between the X-band and VHF radar then X-band radar win hand down in term of detection range. That why your claim that RCS at VHF is only 5 times bigger than in X-band make no sense, because if that is the case than X-band is a much better anti stealth tool.
And you were given figures and official source, you basically just quibbling
We walk in circles.
1. Chinese experts are not an official source, just like Ukrainian experts. The point is simple. You like the Chinese number, but not the Ukrainian one.
2. LM presentation, does not contain figures. The air defense loss graph cannot be compared with the RCS numbers.
3. The words of the LM representative do not contain figures, but only abstractions that can be interpreted as you like.
4. The article of the Air Force Major, has figures. But they were taken from a certain writer. Where did the writer get these figures- I don't know.
In addition, these figures do not agree with other sources for a small RCS. They claim that the RCS B-2 is less than the F-117.
1. Because the Chinese number actually reference a real life incident

2. Yes , it can be compared with number, they very carefully divided the graph into equal section, 5 folds reduction in detection range can be translate to percentage reduction in RCS
3. There is nothing particularly abstraction about golf ball or marble, they have explained before that they often used a ball to talk about RCS as the RCS of it is independent of aspect so easier to imagine.
4. The Air Force Major with all his experiences certainly think the numbers are accurate enough to cite

5. Depend on frequency, at lower frequency it isn't hard to imagine B-2 will have much lower RCS
Understand, if the person was not sure, then he would have picked up a more general word. But he indicates exactly the value (figure).
At the same time, non-standard direction angles, such as 45, 90, etc. And clearly 50.
He gave his estimate by his naked eye, that it. There is no requirement for him to be absolutely accurate with his estimate and given the condition he was in, it is quite impossible for him make super accurate estimate. In high stake situation, people have been shown to misidentify criminal suspects, pilots have been shown to mistaken between the sky and the ocean and die. Those are the things which are much harder to mistaken and people still misidentify them, nevermind something small like a different between 50-65 degrees or even his bank angle.
Let it be a poorly photoshopped picture. Like this one.
View attachment 648151
And as we can both see in that one, the F-22 carry not just 1 but 2 fuel tanks
Well, experts from two Taiwanese institutes believe that the RCS of the F-22 from the nose, at a frequency of 2 GHz is
12 m2
https://www.researchgate.net/public...sign_Key_Factors_and_Limitation_of_Simulation
I understand that you will now say that they are complete fools, because you will not like this figure. But they did the same as the Chinese specialist
On the other hand, I would say that their simulation certainly better than the vague number from the Ukraine. But unlike you, I look deeper than the surface, I care about the model as well
At first, the number seem weird for a stealth aircraft, 10 dBsm at front aspect is quite high even when consider that the model is a perfect conductor and has no RAM or edge treatment. Then I look at their scattering chart and even the breakdown between vertical and horizontal polarization and I find another strange characteristic. The very strong 12 dBsm scattering lobe is directly at the front with very narrow angle. What type of reflector has that scattering characteristic? A flat plate.
Then I look at their model and it all clicked

instead of modelling an S shaped inlet duct, they literally covered it with a flat metal plate. That is why they have such a strong reflection lobes directly in front of the aircraft an in such a narrow angle.
Isn't it strange that they spend such a long time to do such a detail simulation but overlook such obvious detail? Then I read their study and realize that they mentioned that as the primary reason for the high RCS. If you read their study, then you should know the reason for the high RCS value as well.
The S-duct is very important in RCS simulation because not only that it is a strong source of reflection, it is probably the only place on the stealth aircraft where the RAM absorption rating get accumulated to extremely high value of 50-60 dB due to multiple bounce of the signal. I don't blame them though, most simulation doesn't do the inlet correctly or just out right ignore it
We have already found out that we do not know which radars he is comparing on his diagram. And to estimate the RCS from this picture is like looking for numbers in the LM presentation by the percentage of losses from air defense. There is nothing that one could catch on to get at least some numbers. There are not even indirect signs by which something could be determined
There detection range show as km in the photo so you can't say there is no number. The VHF is JY-27, and while there is no mentioned of the exact type of the cm band radar, it is quite safe to conclude that it is something that does similar task to JY-27 and not some crazy comparison like a VHF air defense radar and a missile seeker.